Selenium回放脚本时timeout问题有效解决方案
作者:
吸血鬼日记 发布时间:
[ 2016/5/12 13:50:35 ] 推荐标签:
功能测试 功能测试工具
webdriver的适用代码
1. 在5秒时间内找目标元素,找到针对目标元素执行click
(new WebDriverWait(driver, 5)).until(new ExpectedCondition() {
public WebElement apply(WebDriver d) {
return d.findElement(By.cssSelector("#quick-links > ul > li.nav-tabs-item.mc-ql-tab-item-bm > a"));
}
}).click();
2. 等候页面上出现目标文本,对应IDE的waitForText, waitForElementPresent
//跟据定位类型和定位字符串定位页面元素
protected WebElement findElement(String locatorType, String locatorString) {
if (locatorType.equals(this.CssLocator)) {
return driver.findElement(By.cssSelector(locatorString));
} else if (locatorType.equals(this.IdLocator)) {
return driver.findElement(By.id(locatorString));
} else if (locatorType.equals(this.XpathLocator)) {
return driver.findElement(By.xpath(locatorString));
} else if (locatorType.equals(this.NameLocator)) {
return driver.findElement(By.name(locatorString));
} else if (locatorType.equals(this.ClassNameLocator)) {
return driver.findElement(By.className(locatorString));
} else if (locatorType.equals(this.TagNameLocator)) {
return driver.findElement(By.tagName(locatorString));
} else if (locatorType.equals(this.LinkTextLocator)) {
return driver.findElement(By.linkText(locatorString));
} else {
return driver.findElement(By.partialLinkText(locatorString));
}
}
/**
* Wait 60 seconds till text is present otherwise give timeout error, increase the waiting time if necessary
* @param text
* @param locatorType
* @param locatorString
*/
protected void waitForText(String text, String locatorType, String locatorString){
for (int second = 0;; second++) {
if (second >= 60) fail("timeout");
try {
if (text.equals(findElement(locatorType, locatorString).getText())) break;
} catch (Exception e) {
logger.error("waitForText exception:"+e);
}
try{
Thread.sleep(1000);
} catch (InterruptedException e) {
logger.error("waitForText Thread.sleep exception:"+e);
e.printStackTrace();
}
}
}
执行完某步耗时操作之后,调用waitForText()直到出现目标文本(或者超时)再执行下步动作。